Surface Area Word Problems 7th Grade

Surface Area Grade 6 - Displaying top 8 worksheets found for this concept. Some of the worksheets for this concept are Surface areas of prisms, Grade 6 geometry work, Surface area, Grade 6 geometry work, List college career readiness standards, Surface area of solids, Volume and surface area work, Eureka lessons for 6th grade unit six nets surface. Includes 5 surface area word problems and 5 volume word problems. The great thing about the word problems, is the kids has to figure out if they should use surface area or volume to get the right answer. Surface Area and Volume Activity 7th Grade. Problem 2: A metal box that is in the shape of rectangular prism has the following dimensions. The length is 9 inches, width is 2 inches, and height is 1 1/ 2 inches. Find the total cost of silver coating for the entire.

Problem 1 :

Grade 8 Geometry Problems and Questions with Answers. Geometry problems and questions with answers for grade 8 are presented. These problems and questions deal with calculating angles, perimeters, areas and volumes. Find the total surface area and the volume of a closed cylindrical container with radius 5 cm and a height of 34 cm. Volume and Surface Area Word Problems DRAFT. 72% average accuracy. Volume and Surface.

Erin is making a jewelry box of wood in the shape of a rectangular prism. The jewelry box will have the dimensions shown below. The cost of painting the exterior of the box is $0.50 per square in. How much does Erin have to spend to paint the jewelry box ?

Problem 2 :

A metal box that is in the shape of rectangular prism has the following dimensions. The length is 9 inches, width is 2 inches, and height is 1 1/2 inches. Find the total cost of silver coating for the entire box.

Problem 3 :

Cherise is setting up her tent. Her tent is in the shape of a trapezoidal prism shown below. How many cubic feet of space are in her tent ?

Problem 4 :

Allie has two aquariums connected by a small square prism. Find the volume of the double aquarium.

Solutions

Problem 1 :

Erin is making a jewelry box of wood in the shape of a rectangular prism. The jewelry box will have the dimensions shown below. The cost of painting the exterior of the box is $0.50 per square in. How much does Erin have to spend to paint the jewelry box ?

Solution :

To know that total cost of painting, first we have to know the Surface area of the jewelry box.

Find surface area of the box.

Step 1 :

Identify a base, and find its area and perimeter.

Any pair of opposite faces can be the bases. For example, we can choose the bottom and top of the box as the bases.

Find base area.

B = l x w

B = 12 x 15

B = 180 square in.

Find perimeter of the base.

P = 2(12) + 2(15)

P = 24 + 30

P = 54 in.

Step 2 :

Identify the height, and find the surface area.

The height h of the prism is 6 inches. Use the formula to find the surface area.

S = Ph + 2B

S = 54(6) + 2(180)

S = 684 square inches

Step 3 :

Total cost = Area x Cost per square in.

Total cost = 684 x $0.50

Total cost = $342

So, Erin has to spend $342 to paint the jewelry box.

Problem 2 :

A metal box that is in the shape of rectangular prism has the following dimensions. The length is 9 inches, width is 2 inches, and height is 1 1/2 inches. Find the total cost of silver coating for the entire box.

Solution :

To know that total cost of silver coating, first we have to know the Surface area of the metal box.

Find surface area of the box.

Step 1 :

Identify a base, and find its area and perimeter.

Any pair of opposite faces can be the bases. For example, we can choose the bottom and top of the box as the bases.

Find base area.

B = l x w

7th grade math problems and answers

B = 9 x 2

B = 18 square in.

Find perimeter of the base.

P = 2(9) + 2(2)

P = 18 + 4

P = 22 in.

Step 2 :

Identify the height, and find the surface area.

The height h of the prism is 1 1/2 inches. Use the formula to find the surface area.

Area

S = Ph + 2B

S = 22(1 1/2) + 2(18)

S = 22(3/2) + 36

S = 33 + 36

S = 69 square inches

Step 3 :

Total cost = Area x Cost per square in.

Total cost = 69 x $1.50

Total cost = $103.50

So, the total cost of silver coating for the entire box is $103.50.

Problem 3 :

Cherise is setting up her tent. Her tent is in the shape of a trapezoidal prism shown below. How many cubic feet of space are in her tent ?

Solution :

Step 1 :

To find the number of cubic feet of space in the tent, we have to find the volume of Cherise's tent.

Step 2 :

Volume of Cherise's tent (Trapezoidal prism) is

= base area x height

or

V = b x h

Step 3 :

Find base area.

Area of trapezoid with bases of lengths b₁ and b₂ and height h.

Base area (b) = (1/2) x (b₁ + b₂)h

Base area (b) = (1/2) x (6 + 4)4

Base area = 20 sq.ft

Step 4 :

Find volume of the prism.

V = b x h

V = 20 x 9

V = 180 cubic.ft

So, the number of cubic feet of space in Cherise's tent is 180.

Problem 4 :

Allie has two aquariums connected by a small square prism. Find the volume of the double aquarium.

Solution :

Step 1 :

Find the volume of each of the larger aquariums.

Volume = Base area x Height

Volume = (4 x 3) x 3

Volume = 12 x 3

Volume = 36 cubic ft.

Step 2 :

Find the volume of the connecting prism.

Volume = Base area x Height

Volume = (2 x 1) x 1

Volume = 2 x 1

Volume = 2 cubic ft.

Step 3 :

Add the volumes of the three parts of the aquarium.

V = 36 + 36 + 2

V = 74 cubic ft.

The volume of the aquarium is 74 cubic ft.

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You can also visit the following web pages on different stuff in math.

ALGEBRA

Negative exponents rules

COMPETITIVE EXAMS

APTITUDE TESTS ONLINE

ACT MATH ONLINE TEST

TRANSFORMATIONS OF FUNCTIONS

ORDER OF OPERATIONS

WORKSHEETS

TRIGONOMETRY

Trigonometric identities

MENSURATION

GEOMETRY

ANALYTICAL GEOMETRY

CALCULATORS

Analytical geometry calculators

MATH FOR KIDS

LIFE MATHEMATICS

SYMMETRY

CONVERSIONS

WORD PROBLEMS

HCF and LCM word problems

Word problems on simple equations

Word problems on linear equations

Trigonometry word problems

Word problems on mixed fractrions

OTHER TOPICS

Ratio and proportion shortcuts

Converting repeating decimals in to fractions


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Problem 1 :

Erin is making a jewelry box of wood in the shape of a rectangular prism. The jewelry box will have the dimensions shown below. The cost of painting the exterior of the box is $0.50 per square in. How much does Erin have to spend to paint the jewelry box ?

Problem 2 :

A metal box that is in the shape of rectangular prism has the following dimensions. The length is 9 inches, width is 2 inches, and height is 1 1/2 inches. Find the total cost of silver coating for the entire box.

Problem 3 :

Cherise is setting up her tent. Her tent is in the shape of a trapezoidal prism shown below. How many cubic feet of space are in her tent ?

Problem 4 :

Allie has two aquariums connected by a small square prism. Find the volume of the double aquarium.

Solutions

Problem 1 :

Erin is making a jewelry box of wood in the shape of a rectangular prism. The jewelry box will have the dimensions shown below. The cost of painting the exterior of the box is $0.50 per square in. How much does Erin have to spend to paint the jewelry box ?

Solution :

To know that total cost of painting, first we have to know the Surface area of the jewelry box.

Find surface area of the box.

Step 1 :

Identify a base, and find its area and perimeter.

Any pair of opposite faces can be the bases. For example, we can choose the bottom and top of the box as the bases.

Find base area.

B = l x w

B = 12 x 15

B = 180 square in.

Find perimeter of the base.

P = 2(12) + 2(15)

P = 24 + 30

P = 54 in.

Step 2 :

Identify the height, and find the surface area.

The height h of the prism is 6 inches. Use the formula to find the surface area.

S = Ph + 2B

S = 54(6) + 2(180)

S = 684 square inches

Step 3 :

Total cost = Area x Cost per square in.

Total cost = 684 x $0.50

Total cost = $342

So, Erin has to spend $342 to paint the jewelry box.

Problem 2 :

A metal box that is in the shape of rectangular prism has the following dimensions. The length is 9 inches, width is 2 inches, and height is 1 1/2 inches. Find the total cost of silver coating for the entire box.

Solution :

To know that total cost of silver coating, first we have to know the Surface area of the metal box.

Find surface area of the box.

Step 1 :

Identify a base, and find its area and perimeter.

Any pair of opposite faces can be the bases. For example, we can choose the bottom and top of the box as the bases.

Find base area.

B = l x w

B = 9 x 2

B = 18 square in.

Find perimeter of the base.

Surface Area Word Problems Worksheet

P = 2(9) + 2(2)

P = 18 + 4

P = 22 in.

Step 2 :

Identify the height, and find the surface area.

The height h of the prism is 1 1/2 inches. Use the formula to find the surface area.

S = Ph + 2B

S = 22(1 1/2) + 2(18)

S = 22(3/2) + 36

S = 33 + 36

S = 69 square inches

Step 3 :

Total cost = Area x Cost per square in.

Total cost = 69 x $1.50

Total cost = $103.50

So, the total cost of silver coating for the entire box is $103.50.

Problem 3 :

Cherise is setting up her tent. Her tent is in the shape of a trapezoidal prism shown below. How many cubic feet of space are in her tent ?

Solution :

Step 1 :

To find the number of cubic feet of space in the tent, we have to find the volume of Cherise's tent.

Step 2 :

Volume of Cherise's tent (Trapezoidal prism) is

= base area x height

or

V = b x h

Step 3 :

Find base area.

Area of trapezoid with bases of lengths b₁ and b₂ and height h.

Base area (b) = (1/2) x (b₁ + b₂)h

Base area (b) = (1/2) x (6 + 4)4

Base area = 20 sq.ft

Step 4 :

Find volume of the prism.

V = b x h

V = 20 x 9

V = 180 cubic.ft

So, the number of cubic feet of space in Cherise's tent is 180.

Problem 4 :

Allie has two aquariums connected by a small square prism. Find the volume of the double aquarium.

Solution :

Step 1 :

Find the volume of each of the larger aquariums.

Volume = Base area x Height

Volume = (4 x 3) x 3

Volume = 12 x 3

Volume = 36 cubic ft.

Step 2 :

Find the volume of the connecting prism.

Volume = Base area x Height

Volume = (2 x 1) x 1

Volume = 2 x 1

Volume = 2 cubic ft.

Step 3 :

Add the volumes of the three parts of the aquarium.

V = 36 + 36 + 2

V = 74 cubic ft.

The volume of the aquarium is 74 cubic ft.

Apart from the stuff given above, if you need any other stuff in math, please use our google custom search here.

If you have any feedback about our math content, please mail us :

v4formath@gmail.com

We always appreciate your feedback.

7th Grade Math Word Problems Worksheets

You can also visit the following web pages on different stuff in math.

ALGEBRA

Negative exponents rules

COMPETITIVE EXAMS

APTITUDE TESTS ONLINE

ACT MATH ONLINE TEST

TRANSFORMATIONS OF FUNCTIONS

ORDER OF OPERATIONS

WORKSHEETS

TRIGONOMETRY

Trigonometric identities

MENSURATION

GEOMETRY

ANALYTICAL GEOMETRY

CALCULATORS

Analytical geometry calculators

MATH FOR KIDS

LIFE MATHEMATICS

SYMMETRY

CONVERSIONS

WORD PROBLEMS

Surface Area Word Problems 7th Grade Algebra

HCF and LCM word problems

Word problems on simple equations

Surface Area Word Problems 7th Grade Math

Word problems on linear equations

Trigonometry word problems

Area Word Problems

Word problems on mixed fractrions

OTHER TOPICS

Ratio and proportion shortcuts

Converting repeating decimals in to fractions

Surface Area Word Problems 6th Grade


SBI!